Answer to Question #217278 in Mechanics | Relativity for Julius

Question

The force exerted by a drop of water of pressure P=2.3 x 10⁵Pa on a glass wall of surface area S=0.0042m² is?

Answer 1

Gives

$P=2.3\times10^5 pa\\S=0.0042m^2$

We know that

Pressure

$P=\frac{F}{A}$

$F=P\times A$

$F=2.3\times10^5\times0.0042=966N$