A 3.0L bottle contains a gas at a pressure of 20bars. What volume would the gas occupy at the same temperature if the pressure were 1.0 bar?
We know that
Boyal's law
PV=constant
P1V1=P2V2P_1V_1=P_2V_2P1V1=P2V2
V2=P1V1P2V_2=\frac{P_1V_1}{P_2}V2=P2P1V1
Put value
V2=20×31=60literV_2=\frac{20\times3}{1}=60literV2=120×3=60liter
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments