A light ladder is supported on a rough floor and leans against a rough wall. How far up the ladder can a man climb without slipping taking place?
Solution.

The necessary conditions for mechanical equilibrium for a system of particles.
The vector sum of all external forces is zero:
Projection on OX:
Ff1=N2;
Projection on OY:
mg=N1+Ff2;
The forces of friction:
Ff1=μ1N1;Ff2=μ2N2;μ1 is the coefficient of friction between the ladder and the floor;
μ2 is the coefficient of friction between the ladder and the wall.
μ1N1=N2;N1=μ1N2;mg=N1+μ2N2;mg=μ1N2+μ2N2;N2=1+μ1μ2μ1mg.
The sum of the moments of all external forces about line O is zero:
N2cosαl+Ff2sinαl−mgcosαx=0;mgcosαx=N2cosαl+Ff2sinαl;mgcosαx=N2cosαl+μ2N2sinαl;mgcosαx=N2l(cosα+μ2sinα);mgcosαx=1+μ1μ2μ1mgl(cosα+μ2sinα);x=1+μ1μ2μ1mgl⋅mgcosα(cosα+μ2sinα);x=1+μ1μ2μ1l⋅cosα(cosα+μ2sinα);h=xcosα;h=1+μ1μ2μ1l⋅cosα(cosα+μ2sinα)cosα;h=1+μ1μ2μ1l(cosα+μ2sinα).
Answer:
h=1+μ1μ2μ1l(cosα+μ2sinα).