Question #21642

what is the magnitude o a net force to stop a 100kg object moving at 1 m/s in 5 seconds

Expert's answer

What is the magnitude of a net force to stop a 100kg object moving at 1 m/s in 5 seconds?

**Solution.**


m=100kg,v0=1ms,t=5s;m = 100kg, v_0 = 1\frac{m}{s}, t = 5s;F?F - ?


**Newton's second law:**


ma=F;ma = F;a=Fm;a = \frac{F}{m};


**Velocity is:**


v=v0at;v = v_0 - at;


**The object stopped, then**


v=0v = 00=v0at;0 = v_0 - at;a=v0t;a = \frac{v_0}{t};Fm=v0t;\frac{F}{m} = \frac{v_0}{t};F=mv0t.F = \frac{m v_0}{t}.F=10015=20(N).F = \frac{100 \cdot 1}{5} = 20(N).


**Answer:** F=20NF = 20N.


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