Answer to Question #215708 in Mechanics | Relativity for Manic

Question

in an experiment, the following readings where observed; volume of alcohol flow pair minutes is 10^-5m^3, the density of alcohol is 800kg\m^3, length of tube is 0.5m, radius of tube is 0.05cm and the height of alcohol is 60cm. calculate the coefficient of viscosity of alcohol?

Answer 1

$V=10^{-5}m^3min^{-1}=\frac{10^{-5}}{60}m^3s^{-1}\\ \rho=800kgm^{-3}\\ l=0.5m\\ r=0.05cm=5\times{10^{-4}}m\\ h=60cm=0.6m\\$

Pressure P is

$P=h\rho{g}\\ g=10ms^{-2}\\ P=10\times{0.6}\times{800}=4800Nm^{-2}\\$

Coefficient of viscosity is given by Poiseuille's formula

$\eta=\dfrac{\pi{P}r^4}{8Vl}\\ \eta=\dfrac{\pi{4800}(5\times10^{-4})^4}{8\times\frac{10^{-5}}{60}\times0.5}\\ \eta=1.41\times10^{-3}Nsm^{-2}$