Question #21560

A tank 5m high is half filled with water and then is filled to the top with oil of density 0.85 g cm cube. What is the pressure at the bottom of the tank due to these liquid?

Expert's answer

A tank 5m high is half filled with water and then is filled to the top with oil of density 0.85 g cm cube. What is the pressure at the bottom of the tank due to these liquid?

**Solution:**

Pressure at the bottom of the tank (P)=(P) = pressure by water level ++ pressure by the oil =h1d1g+h2d2g.= h_{1}d_{1}g + h_{2}d_{2}g.

Given that


h1=h2=2.5mh_{1} = h_{2} = 2.5\,md1=1000kgm3d_{1} = 1000\,\frac{kg}{m^{3}}d2=850kgm3d_{2} = 850\,\frac{kg}{m^{3}}g=9.8ms2g = 9.8\,\frac{m}{s^{2}}P=9.8×(1000×2.5+850×2.5)P=45325Pa4.5kPa.P = 9.8 \times (1000 \times 2.5 + 850 \times 2.5) \Rightarrow P = 45325\,Pa \approx 4.5\,kPa.


Answer: P4.5kPaP \approx 4.5\,kPa.

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