Compton shift in wavelength is zero scattering angle of photon is:
a= 90
b=180
c=0
d=45
We know that
λ′−λ=hm0c(1−cosϕ)\lambda'-\lambda=\frac{h}{m_0c}(1-cos\phi)λ′−λ=m0ch(1−cosϕ)
∆λ=hm0c(1−cosϕ)\lambda=\frac{h}{m_0c}(1-cos\phi)λ=m0ch(1−cosϕ)→(1)\rightarrow(1)→(1)
Given
∆λ=0∆\lambda=0∆λ=0
equation (1) put value
0=hm0c(1−cosϕ)0=\frac{h}{m_0c}(1-cos\phi)0=m0ch(1−cosϕ)
1−cosϕ=01-cos\phi=01−cosϕ=0
cosϕ=1cos\phi=1cosϕ=1
ϕ=cos−1(−1)=180°\phi=cos^{-1}(-1)=180°ϕ=cos−1(−1)=180°
Option (b) is correct
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