Answer to Question #214320 in Mechanics | Relativity for Flint

Question

A body slides down a rough inclined plane of angle 30° to the horizontal.find the distance covered after 15s from rest, assuming g=9.8m/s²

Answer 1

Gives

$\theta=30°$

t=15sec

g=9.8m/sec$^2$

$F=mgsin\theta$

$ma=mgsin\theta$

$a=gsin\theta$

$s=ut+\frac{1}{2}at^2$

$s=0+\frac{1}{2}(gsin\theta)t^2$

$$s=\frac{1}{2}\times9.8\times sin30°\times15^2=551.25m$$