Answer to Question #214320 in Mechanics | Relativity for Flint

Question #214320

A body slides down a rough inclined plane of angle 30° to the horizontal.find the distance covered after 15s from rest, assuming g=9.8m/s²


1
Expert's answer
2021-07-07T11:37:33-0400

Gives

θ=30°\theta=30°

t=15sec

g=9.8m/sec2^2

F=mgsinθF=mgsin\theta

ma=mgsinθma=mgsin\theta

a=gsinθa=gsin\theta

s=ut+12at2s=ut+\frac{1}{2}at^2

s=0+12(gsinθ)t2s=0+\frac{1}{2}(gsin\theta)t^2


s=12×9.8×sin30°×152=551.25ms=\frac{1}{2}\times9.8\times sin30°\times15^2=551.25m


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