A body slides down a rough inclined plane of angle 30° to the horizontal.find the distance covered after 15s from rest, assuming g=9.8m/s²
Gives
θ=30°\theta=30°θ=30°
t=15sec
g=9.8m/sec2^22
F=mgsinθF=mgsin\thetaF=mgsinθ
ma=mgsinθma=mgsin\thetama=mgsinθ
a=gsinθa=gsin\thetaa=gsinθ
s=ut+12at2s=ut+\frac{1}{2}at^2s=ut+21at2
s=0+12(gsinθ)t2s=0+\frac{1}{2}(gsin\theta)t^2s=0+21(gsinθ)t2
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