Question

Two people carry a heavy object by placing it on a uniform board that is 2 meters long and weighs 200N. One person lifts at one end with a force of 400N, and the other lifts the opposites end with a force of 600N. Find the weight and the location of the heavy object. 

Answer 1

Solution.

$l=2m;$

$F_1=400N;$

$F_2=600N;$

$F_3=200N;$

$F_1+F_2=F+F_3\implies F=F_1+F_2-F_3;$

$F=400N+600N-200N=800N;$

$T_{net}=Fx+F_3(l/2)-F_2l=0;$

$800x+200-1200=0;$

$800x=1000;$

$x=1000/800=1.25m;$

Answer: $F=800N;$

$x=1.25m.$