Question #211457

In the figure shown below two new cast iron pipes in series, D1 =0.8m, D2 =0.6m the first pipe of length of L1=400m, while the second of length of L2=350m, level at A =120m, Q = 0.1.5m3/s (T=25oC).there are a sudden contraction between Pipe 1 and 2, and Sharp entrance at pipe 1. Fine the total head of energy losses

1
Expert's answer
2021-06-29T08:21:40-0400
A1=πd2=3.14×(0.4)2=0.5024m2A_1=\pi d^2=3.14\times(0.4)^2=0.5024m^2

A2=πd2=3.14×(0.3)2=0.2826m2A_2=\pi d^2=3.14\times(0.3)^2=0.2826m^2

V1=A1L2=0.5024×400=200.96m3V_1=A_1L_2=0.5024\times400=200.96m^3

V2=A2L2=0.2826×350=98.91m3V_2=A_2L_2=0.2826\times350=98.91m^3

Total heat of energy losses


Q1=AV1=120×200.96=24.11JQ_1=AV_1=120\times200.96=24.11J

Q2=AV2=120×98.91=11.86JQ_2=AV_2=120\times98.91=11.86J


Q=Q1Q2=24.1111.86=12.25J∆Q=Q_1-Q_2=24.11-11.86=12.25J


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