Find the length of a side of a cube having a mass of 3.2 kg and the density of nuclear matter.
take the density of nuclear matter=2.3×1017kg/m3=2.3\times 10^{17}kg/m^3=2.3×1017kg/m3
volume,V=massdensity=3.22.3×1017=1.39×10−17m3volume, V=\frac{mass}{density}=\frac{3.2}{2.3\times 10^{17}}=1.39\times 10^{-17}m^3volume,V=densitymass=2.3×10173.2=1.39×10−17m3
l=(1.39×10−17)1/3=2.405×10−6ml=({1.39\times 10^{-17}})^{1/3}=2.405\times 10^{-6}ml=(1.39×10−17)1/3=2.405×10−6m
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