Question

A 59,300 kg plane moves at 254 m/s. What is the plane’s kinetic energy?

Answer 1

K.E = $\frac{1}{2}mv^2$

Here,

m = 59300 kg

v = 254 m/s

Hence,

K.E = $\frac{1}{2}\times59300\times(254)^2$

= 1.91 $\times$ 10⁹ J.