A 59,300 kg plane moves at 254 m/s. What is the plane’s kinetic energy?
K.E = "\\frac{1}{2}mv^2"
Here,
m = 59300 kg
v = 254 m/s
Hence,
K.E = "\\frac{1}{2}\\times59300\\times(254)^2"
= 1.91 "\\times" 109 J.
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