A fan motor uses 8310 J of energy in 9.44 s. This energy is used to accelerate a 8.12 kg blade to 19.7m/s in 3.10 s. What is the efficiency of the fan? Leave your answer as a decimal.
Solution.
Wm=8310J;W_m=8310J;Wm=8310J;
tm=9.44s;t_m=9.44s;tm=9.44s;
m=8.12kg;m=8.12kg;m=8.12kg;
v=19.7m/s;v=19.7m/s;v=19.7m/s;
t=3.10s;t=3.10s;t=3.10s;
WK=mv22;W_K=\dfrac{mv^2}{2};WK=2mv2;
WK=8.12⋅19.722=1575.6J;W_K=\dfrac{8.12\sdot19.7^2}{2}=1575.6J;WK=28.12⋅19.72=1575.6J;
Pout=WKt;P_{out}=\dfrac{W_K}{t};Pout=tWK;
Pout=1575.63.10=508.3w;P_{out}=\dfrac{1575.6}{3.10}=508.3w;Pout=3.101575.6=508.3w;
Pin=83109.44=880.3w;P_{in}=\dfrac{8310}{9.44}=880.3w;Pin=9.448310=880.3w;
efficiency=PoutPin;efficiency=\dfrac{P_{out}}{P_{in}};efficiency=PinPout;
efficiency=508.3880.3=0.58;efficiency=\dfrac{508.3}{880.3}=0.58;efficiency=880.3508.3=0.58;
Answer:efficiency=0.58;efficiency=0.58;efficiency=0.58;
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