Question

A 60 kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?

Answer 1

Question#21031

A 60 kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?

Solution:

The work done against gravity is equal to the changing of potential energy:

$$A = \Delta E _ {p} = m g \Delta H$$ $$A = 6 0 * 9. 8 * 4 = 2 3 5 2 J$$

Answer: 2352 J