Answer to Question #210178 in Mechanics | Relativity for Vector vee

Question #210178

a=I+2j-3k

b=4i+j-7k.

Find the modulus and direction cosine of the following

b+a

b-a







1
Expert's answer
2021-06-23T17:05:26-0400

1)


b+a=(5,3,10)b+a=134(cosa,cosb,cosc)=1134(5,3,10)\bold{b+a}=(5,3,-10)\\b+a=\sqrt{134}\\ (\cos a,\cos b,\cos c)=\frac{1}{\sqrt{134}}(5,3,-10)

2)


ba=(3,1,4)ba=26(cosa,cosb,cosc)=126(3,1,4)\bold{b-a}=(3,-1,-4)\\b-a=\sqrt{26}\\ (\cos a,\cos b,\cos c)=\frac{1}{\sqrt{26}}(3,-1,-4)


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