Question

A stone ot mass 2.0 kg to pulled a long a horizontal path by a rope which makes an angel 60° with the horizontal neglecting frictions. Calculate the tension in the rope of the body accelerate uniformly at 5.0 m5-2

Answer 1

Gives

Mass(m)=2.0kg

a=5m/sec²

$\theta=60°$

$F=ma$

$F=2\times5=10N$

Tansion horizontal components

F=Tcos$\theta$

$T=\frac{F}{cos\theta}$

$T=\frac{10}{cos60°}=20N$