Question

A projectile is launched horizontally with the velocity of 30 milliseconds after 3 milliseconds at the magnitude of the vertical component of velocity is approximately
what milliseconds at the magnitude of the vertical component of velocity is approximately what a second

Answer 1

Task:

A projectile is launched horizontally with the velocity of $30\frac{m}{0.001s} = 30000\frac{m}{s}$ . What is the magnitude of the vertical component of velocity after 3 milliseconds? What is the magnitude of the vertical component of velocity after 1 second?

Solution:

$$h (t) = \frac {g \cdot t ^ {2}}{2} = \frac {v _ {y} (t) ^ {2}}{2 g}$$ $$v _ {y} (0. 0 0 3 s) = \sqrt {g ^ {2} \cdot t ^ {2}} = g \cdot t = 9. 8 1 \cdot 0. 0 0 3 \frac {m}{s} = 0. 0 2 9 4 3 \frac {m}{s}$$ $$v _ {y} (1 s) = \sqrt {g ^ {2} \cdot t ^ {2}} = g \cdot t = 9. 8 1 \cdot 1 \frac {m}{s} = 9. 8 1 \frac {m}{s}$$

Answer:

$$v _ {y} (0. 0 0 3 s) = 0. 0 2 9 4 3 \frac {m}{s}$$ $$v _ {y} (1 s) = 9. 8 1 \frac {m}{s}$$