Question #20699
A 2kg iron block is taken from a furnace where its temperature was 650 C and placed on a large block of ice at 0C. assuming that all the heat given up by the iron is used to melt the ice, how much ice is melted?
Expert's answer
M - mass of melted ice
m - mass of iron (2 kg)
c - specific heat of iron
L - Enthalpy of fusion of ice
Iron cold from 650 C to 0 C and give all heat to the ice.Q1=Q2;
L*M=m*c*(t2-t1)
M=m*c*(t2-t1)/L=(460*2*(650-0))/(3.3*10^5)=1.812 kg
m - mass of iron (2 kg)
c - specific heat of iron
L - Enthalpy of fusion of ice
Iron cold from 650 C to 0 C and give all heat to the ice.Q1=Q2;
L*M=m*c*(t2-t1)
M=m*c*(t2-t1)/L=(460*2*(650-0))/(3.3*10^5)=1.812 kg
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