Question #206543

Show that the light from a source which is moving away from us with a speed of

0.6c has twice the wavelength it has in the frame of reference of the source.



1
Expert's answer
2021-06-13T11:29:24-0400

We can use the relativistic Doppler Effect equation in this problem.

For a source of light moving away from the observer, the wavelength of light measured by the observer will be:

λ=λ01+β1βλ=λ_0 \sqrt{ \frac{1+β}{1-β} }

λ0 is the wavelength of light in frame of reference of the source

We can compute the β value as

β=vcβ=0.6ccβ=0.6β = \frac{v}{c} \\ β = \frac{0.6c}{c} \\ β =0.6

Substitute the β value:

λ=λ01+0.610.6λ=λ04λ=2λ0λ=λ_0 \sqrt{ \frac{1+0.6}{1-0.6} } \\ λ=λ_0 \sqrt{4} \\ λ=2λ_0

The light from a source which is moving away from us with a speed of 0.6c has twice the wavelength it has in the frame of reference of the source.


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