Question

If you use a marble of radius 13 mm for mercury, how far from the sun must you place your outpost planet?

Answer 1

Solution.

$r=13mm=0.013m;$

$R_M=2440km=2440000m;$

$D=57.9\sdot 10^9m;$

$\dfrac{R_M}{r}=\dfrac{D}{d}\implies d=\dfrac{D\sdot r}{R_M};$

$d=\dfrac{57.9\sdot10^9m\sdot0.013m}{2440000m}=308m;$

Answer: $d=308m.$