Question#20302
250N force is required to raise 75 kg mass from a pulley. if rope is pulled 12m then load is lifted to 3m, the efficiency of pulley system will be
Solution:
Let:
m=75 kgH=3 mS=12 mF=250 N
η−?
According to the law of conservation energy:
ηFmg=HSη=SFmgHη=12÷25075÷9.8÷3=0.735=73.5%
Answer: 73.5%