The 500-N weight is supported by two cables, the cable forces being F1 and F2. Knowing that the resultant of F1 and F2 is a force of magnitude 500 N acting in the y-direction, determine F1 and F2.
Gives
"F=500N"
Assume diagram
Force horizontal components
"\\Sigma F_H=0"
"-T_1cos 35\u00b0+T_2cos50\u00b0=0"
"T_2=\\frac{T_1cos35}{cos50}"
Vertical components
"\\Sigma F_v=0"
"T_1sin35\u00b0+T_2sin50\u00b0-500=0"
Put T2 value
"T_1=322.631477N"
"T_2=T_1\\frac{cos35\u00b0}{cos50\u00b0}"
"T_2=411.14N"
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