Question

A particle is fired at 22 degrees with respect to an incline and then hits a point on the incline as label. If the initial velocity is 15 m/s, a. find the time it takes for the projectile to hit the incline plane. b. find the distance from launching point to the landing point.

Answer 1

Gives

$\theta=22°$

Velocity= 15 m/sec

Part (a)

Time take projectile to hit the inclined plane

$t=\frac{usin\theta}{g}$

$t=\frac{15\times sin22}{9.8}$

$t=0.574$ sec

Total time launching point to landing point

$T=\frac{2usin\theta}{g}$

Put value

$T=\frac{2\times15\times sin22}{9.8}$

$T=1.15$ sec

Part(b)

Distance from lonching to landing

$R=\frac{u^2sin2\theta}{g}$

Put value

$R=\frac{15^2\times sin44}{9.8}$ =15.94m