Answer to Question #200655 in Mechanics | Relativity for Master j

Question

Air is compressed in a cylinder of a diesel engine. The initial volume of the air is 800cm³ and a temperature of 27^oC and a pressure of 100kPa. The air compressed to one-fifteenth of its initial volume so that its temperature reaches 600^oC. Determine the final pressure of the air.

Answer 1

Gives

$T_1=27°C=300K$

$P_1=10^5pa$

$T_2=600°C=873K$

$V_1=8\times10^{-4}m^3$

$V_2=\frac{V_1}{15}$

$P_2=?$

Gas equation

PV= nRT

n=1mol

$P_2=\frac{P_1V_1}{V_2}\times\frac{T_2}{T_1}$

Put values

$$P_2=\frac{10^5\times V_1}{\frac{V_1}{15}}\times\frac{873}{300}=4365Kpa$$

$P_2=4365 Kpa$