Question #200297

Two carts 1 and 2 move along a straight line towards each other as shown in Figure A and collide head-on. The graph shown in the diagram depicts the force F12 exerted by cart 1 on cart 2 during the collision, as a function of time, direction and positive is selected to be in the right direction. Given that the mass of cart 1 is m1 = 0.2kg and its velocity before the collision is v1 = 3m / s in the positive direction, and the mass of the cart 2 m2 = 0.8kg and its velocity before the collision is v2 = 3m / s in the negative direction.


A. Copy the graph in Figure B to your page and add to this graph (in the same system of axes) a graph depicting the force exerted by cart 2 on cart 1 (force F21) during the collision. 

B Calculate the speed of each of the carts immediately after the collision. 

C. Is the collision completely elastic? Necrosis. 


https://ibb.co/7tS4dBy

https://ibb.co/r5ShBzW



1
Expert's answer
2021-05-30T13:32:27-0400

Part a



Part b

Consider the conservation of momentum

(m1v1+m2v2)i=(m1v1+m2v2)f(m_1v_1+m_2v_2)_i=(m_1v_1+m_2v_2)_f

0.23+0.83=0.2v1+0.8v20.2*3+0.8*3=0.2v_1+0.8v_2

0.2v1+0.8v2=30.2v_1+0.8v_2=3


Also, consider conservation of kinetic energy

(v1)i+(v1)f=(v2)i+(v2)f(v_1)_i+(v_1)_f=(v_2)_i+(v_2)_f

3+v1=3+v23+v_1=3+v_2

v1=v2v_1=v_2


0.2v1+0.8v1=30.2v_1+0.8v_1=3

v1=3m/s    v2=3m/sv_1=3m/s \implies v_2 =3m/s


Part 3

This is a completely elastic collision. There is no loss of kinetic energy in the collision.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS