Question

A piston moves from rest to a speed of 5 m/s in one twenty-fifth of a second. What are the average acceleration and the distance travelled?

Answer 1

$t =\frac{1}{25}=0.04$

$\vec v_0=0;\vec v_1=5$

$\vec a=\frac{\vec v_1-\vec v_0}{t}=\frac{5}{0.04}=125$

$\vec s=\vec v_0t+\frac{at^2}{2}=\frac{125*0.04^2}{2}=0.1$

$\text{Answer: }\vec a=125\frac{m}{s^2};\vec s=0.1m$