Answer to Question #199758 in Mechanics | Relativity for Master j

Question

A 500 g bar of ice is initially at -25 °C. Calculate the amount of energy required to vapourize 25% of the substance at 100 °C

Answer 1

Specific heat capacity for Ice = 2.1 J/g°C

Latent heat of fusion of Ice = 335 J/g

Specific heat capacity for Water = 4.2 J/g°C

Latent heat of evaporation: 2256 J/g

$Q_1 = 25\times 500 \times 2.1 = 26250 \;J$ (from -25 °C to 0 °C)

$Q_2 = 100 \times 500 \times 4.2 = 210000 \;J$ (from 0 °C to 100 °C)

$Q_3 = 500 \times 335 = 167500 \;J$ (heat of melting)

$Q_4 = 500 \times 2256 = 1128000 \;J$ (heat of evaporation)

Total heat $Q_T = 26250+210000+167500+1128000= 1531750 \;J$

$Q_{0.25}=1531750 \times 0.25=382937.5 \;J = 382.93 \;kJ$

Answer: 382.93 kJ