Question #19970

Two trains are moving each other at velocities of 36 km/h and 54 km/h . A passenger in the first train observes that the second train passes his train in a time interval of 6 seconds . what is length of second train ?

Expert's answer

Question

Given:


v1=36kmh=10msv2=54kmh=15mst=6 s\begin{array}{l} v_{1} = 36 \frac{km}{h} = 10 \frac{m}{s} \\ v_{2} = 54 \frac{km}{h} = 15 \frac{m}{s} \\ t = 6 \text{ s} \end{array}


Need to find: Length of the second train.

Solution:

The passengers of the first train see that the second train moving with the velocity which is equal to the sum of the first and second trains' velocities: v=v1+v2v = v_{1} + v_{2}. Then the length of the second train is L2=vt=(v1+v2)t=(10+15)6=150mL_{2} = v \cdot t = (v_{1} + v_{2}) \cdot t = (10 + 15) \cdot 6 = 150 \, \text{m}.

Answer: the length of the second train is 150 meters.

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