
mc=20kgmp=5kg(vp)1=10m/s
The expression of the velocity in the horizontal direction:
(vp)1H=54(vp)1(vp)1H=54×10=8m/s
Since the external force is zero, therefore the momentum is conserved. Write the expression of the conservation of the momentum.
mc(vc)1H+mp(vp)1H=mc(v2)+mp(v2)mc(vc)1H+mp(vp)1H=(mc+mp)(v2)20×0+5×8=(20+5)(v2)v2=2540=1.6m/s
Answer: 1.6 m/s
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