Question #199344

The cart and package have a mass of 20 kg and 5 kg respectively. If the card has a smooth surface and it is initially at rest, while the velocity of the package is as shown, determine the final velocity of the cart and package after in the impact.


1
Expert's answer
2021-05-27T08:31:31-0400

mc=20  kgmp=5  kg(vp)1=10  m/sm_c=20\;kg \\ m_p = 5\;kg \\ (v_p)_1=10\;m/s

The expression of the velocity in the horizontal direction:

(vp)1H=45(vp)1(vp)1H=45×10=8  m/s(v_p)_{1H}=\frac{4}{5}(v_p)_1 \\ (v_p)_{1H}=\frac{4}{5} \times 10 = 8 \;m/s

Since the external force is zero, therefore the momentum is conserved. Write the expression of the conservation of the momentum.

mc(vc)1H+mp(vp)1H=mc(v2)+mp(v2)mc(vc)1H+mp(vp)1H=(mc+mp)(v2)20×0+5×8=(20+5)(v2)v2=4025=1.6  m/sm_c(v_c)_{1H}+m_p(v_p)_{1H}=m_c(v_2)+m_p(v_2) \\ m_c(v_c)_{1H}+m_p(v_p)_{1H}=(m_c+m_p)(v_2) \\ 20 \times 0 + 5 \times 8 = (20 + 5)(v_2) \\ v_2 = \frac{40}{25}=1.6 \;m/s

Answer: 1.6 m/s


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