Question

A roller-coaster car with a mass of 500kg moves at the bottom of a circular dip of radius 40.0m with a speed of 10.0m/s. Find the normal force of the track on the car at the bottom of the dip. 

Answer 1

Mass(m)=500kg

Radius (r)=40 m

Speed(v)=10.00m/sec

Force=?

$a_c=\frac{v^2}{r}$

Put value

$a_c=\frac{10^2}{40}=\frac{100}{40}=2.5m/sec^2$

Force

F=ma_c

Put value

$F=500\times2.5N$

$F=1250N$