Answer to Question #198354 in Mechanics | Relativity for Arlene Joy S. Domd

Question

A stunt car travelling toward the edge of a cliff at 25 meters measured horizontally from the edge of the cliff.

A. How much time does it take the car to reach the ground?

B. Determine the height of the cliff.

Answer 1

Gives

R=25m

time(t)=?

Hight(h)=?

Newton's 2^nd law

$S=ut+\frac{1}{2}at^2$

u=0

a=g

$s=\frac{1}{2}gt^2$

$t=\sqrt\frac{2s}{g}$

Put value

$t=\sqrt\frac{2\times25}{9.8}$ =2.259 sec

Newton's 3^rd rules

$v^2=u^2+2as$

u=0

a=g

$v^2=2as$

$s=\frac{v^2}{2a}$

$v=\sqrt{2gs}$

$v=\sqrt{2\times9.8\times25}$

v=22.13m/sec

d$=u\times t$

d=$22.13\times2.259=50m$