Question #197983

is considered circular with a diameter of 2b. A participant starts his vehicle manages to increases his speed at a constant rate of α. Obtain a simplified expression between his velocity and his acceleration as a function of time


1
Expert's answer
2021-05-25T09:29:58-0400

We know that circuler path particle move

Then two force are work

Fext=mv2bF_{ext}=\frac{mv^2}{b}

Fext=mαF{ext}=m\alpha

mα=mv2bm\alpha=\frac{mv^2}{b}

α=v2b\alpha=\frac{v^2}{b}

Where b radius of circuler path


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