Question #196163

Prove collision (of tennis ball) was elastic with a Velocity - time graph (Tip: calculate the distance)


1
Expert's answer
2021-05-20T18:22:52-0400

Kinematic equations for objects in free-fall:

v=v0gtv=v_0-gt

y=y0+v0tgt2/2y=y_0+v_0t-gt^2/2


Let v0=0,y0=10v_0=0,y_0=10

Then:

v=9.8tv=-9.8t

y=104.9t2y=10-4.9t^2

t=10/4.9=1.43 st=\sqrt{10/4.9}=1.43\ s -the ball falls on the ground


After collision equations become:

v=9.8(t1.43)v=9.8(t-1.43)

y=4.9(t1.43)2y=4.9(t-1.43)^2




From graphs we can see that the ball falls on the ground after 1.43 s1.43\ s , and after the same time it rises to the height of 10 m10\ m. So, the collision is elastic.



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