Question

With what impulse does a 0.50kg newspaper have to be thrown to give it a velocity of 3 m/s

Answer 1

$m = 0.5\ kg$

$\vec v_0= 0;$

$\vec v_1= 3\frac{m}{s};$

$\Delta \vec p= m\Delta\vec v= m(\vec v_1-\vec v_0)= 0.5*3 = 1.5\ kg\frac{m}{s}$

$\text{Answer: }1.5\ kg\frac{m}{s}$