Question #19337

an object falls freely from rest for 5 seconds. Find the distance travelled in the last 2 seconds. (g=9.8m/s square)

Expert's answer

Question#19337

an object falls freely from rest for 5 seconds. Find the distance travelled in the last 2 seconds. (g=9.8m/s square)

Solution:

The distance is:

H=H0H1H = H_0 - H_1, were H0H_0 – full distance travelled from 5 sec, H1H_1 – distance travelled at first 3 sec

H=gt02/2gt12/2H = gt_0^2 / 2 - gt_1^2 / 2, were t0=5t_0 = 5 sec., t1=3t_1 = 3 sec,

H=9.852/29.832/2=78.4mH = 9.8 * 5^2 / 2 - 9.8 * 3^2 / 2 = 78.4 \, \text{m}

Answer: 78.4 m.

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