Question

Standing waves are established in a string. The frequency of the wave is 512 Hz and the 

distance between two successive nodes is 8 cm. Calculate the velocity of the wave in the 

string.

Answer 1

velocity of wave = frequency $\times$ wavelength

wavelength = 8 cm = 0.08 m

Frequency(n)= 512 Hz

the distance between two nodes represents half wavelength = $\frac{1}{2}\lambda$

v=$n\lambda$

wavelength = 2$\times$ 0.08 = 0.16 $m$

v=$n\lambda$

v=$512\times0.16$ m/sec

v=81.92m/sec

Velocity of wave

v=81.92m/s