A standing wave is set up in a string 120 cm long. The string vibrates in four segments under
a frequency of 120 Hz. Calculate the wavelength and the fundamental frequency of the string
L=120 cm=1.2 mL =120\ cm =1.2 \ mL=120 cm=1.2 m
n = 4 \
λ=2n∗L=24∗1.2=0.6\lambda= \frac{2}{n}*L= \frac{2}{4}*1.2=0.6λ=n2∗L=42∗1.2=0.6
f=120f = 120f=120
f=fn∗n;fn=fn=1204=3f= f_n*n;f_n= \frac{f}{n}= \frac{120}{4}=3f=fn∗n;fn=nf=4120=3
Answer : λ=0.6 m;f4=30 Hz\text {Answer : }\lambda = 0.6\ m ; f_4= 30\ HzAnswer : λ=0.6 m;f4=30 Hz
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