When the frictionless system where a 6kg block is pushing a 3kg block is accelerated by an applied force of magnitude F, the tension in the string between the blocks is
(A) F (B) (2/3) F (C) ½ F (D) (1/3) F
answer : (b) (2\3) F
ACCORDING TO GIVEN QUESTION FIG. IS:
As we are applying force F (pushing it) on 3 Kg block ,
acceleration of 3 kg block will be
by newtons law T1=T2
and T1 =ma
= 6 X a
="6 \\times {F\\over9}"
="{2\\over3}F" .......................answer
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