Question #19151

An 80 kg man climbs a 50 m-high hill in 20 minutes. What is the average power in watts he expends climbing the hill?

Expert's answer

Question#19151

An 80 kg man climbs a 50 m-high hill in 20 minutes. What is the average power in watts he expends climbing the hill?

Solution:

Let:


m=50 kgm = 50 \text{ kg}H=50 mH = 50 \text{ m}t=20 min=1200 sect = 20 \text{ min} = 1200 \text{ sec}


W-?

W=At\mathbf{W} = \frac{\mathbf{A}}{t}, were A- the done work

Such as the done work is equal to change a potential energy:


A=ΔEp=mgH, g=9,8 m/s2A = \Delta E_p = mgH, \text{ g} = 9,8 \text{ m/s}^2W=mgHt\mathbf{W} = \frac{mgH}{t}W=50×9.8×501200=20.42 watt\mathbf{W} = \frac{50 \times 9.8 \times 50}{1200} = 20.42 \text{ watt}


Answer: 20,42 watt.

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