Question#19151
An 80 kg man climbs a 50 m-high hill in 20 minutes. What is the average power in watts he expends climbing the hill?
Solution:
Let:
m=50 kgH=50 mt=20 min=1200 sec
W-?
W=tA, were A- the done work
Such as the done work is equal to change a potential energy:
A=ΔEp=mgH, g=9,8 m/s2W=tmgHW=120050×9.8×50=20.42 watt
Answer: 20,42 watt.