Question #191450

A bus travelling at a constant velocity of 72km/he passes a stationary car. After a time lapse of 1/6 minutes, the car accelerates uniformly at 3m/s^2 to reach a speed of 108km/hr and maintains this speed afterwards. Draw the speed-time graph and find when and where the car overtakes the bus.


1
Expert's answer
2021-05-11T09:07:29-0400

Velocity of bus, vb=72 km/h=20 m/sv_b=72\space km/h=20\space m/s

Velocity of car, vc=108 km/h=30 m/sv_c=108\space km/h=30\space m/s

Acceleration of car, ac=3 m/s2a_c=3\space m/s^2

Acceleration of bus, ab=0a_b=0

Initial separation of bus and car, s=20×10=200 ms=20\times10=200\space m

Velocity of bus with respect to car, vbc=vbvc=10 m/sv_{bc}=v_b-v_c=-10\space m/s

Acceleration of bus with respect to car, abc=3 m/s2a_{bc}=-3\space m/s^2

time taken by car to reach bus =t=t

s=ut+12at2s=ut+\dfrac{1}{2}at^2

200=10t+12(3)t2-200=-10t+\dfrac{1}{2}(-3)t^2

3t2+20t200=03t^2+20t-200=0

t=5.48 st=5.48\space s


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Comments

King
13.05.21, 12:13

Thanks a lot.

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