Question #19082

The graph shown describes a certain force that is exerted on an object, as a function of the position of the object. How much work is done by this force as the object moves from the position 0.0 m to 6.0 m?

Expert's answer

The graph shown describes a certain force that is exerted on an object, as a function of the position of the object. How much work is done by this force as the object moves from the position 0.0m0.0\mathrm{m} to 6.0m6.0\mathrm{m} ?



Solution

The work that done by this force is equal to the area under the curve F(x)F(x) . So


A=42+(2)3+01=2JA = 4 * 2 + (- 2) * 3 + 0 * 1 = 2 J

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