Question #188484

what is the flight time of a cannon fires a cannonball with a muzzle velocity of 50.0 m/sec at an angle of 40 degrees.


1
Expert's answer
2021-05-04T11:30:49-0400

To be given in question

Initial velocity (u)=50m/sec

g=9.8m/sec2g=9.8m/sec^2

θ=40°\theta=40°

To be asked in question

Total time in flight

T=?

We know that

T=2usinθg(1)T=\frac{2usin\theta}{g}\rightarrow(1)

Put value in eqution (1)

T=2×50×sin(40°)9.8T=\frac{2\times 50\times sin(40°)}{9.8}

T=6.55 sec


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