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Answer to Question #18769 in Mechanics | Relativity for Mark
Question #18769
. A 980 kg car traveling at 20 m/s rounds a curve of radius 40 m. What is the friction force that must act on the car to keep it in its circular path?
Expert's answer
Friction force is equal to centrifugal in this case
F_f=F_c = mv^2/r = 980*20^2/40 =9800 N
F_f=F_c = mv^2/r = 980*20^2/40 =9800 N
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