An automobile tire having a temperature of 7.9 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 24 lb/in2 . What would be the gauge pressure in the tire when its temperature rises to 26◦C? For simplicity, assume that the volume of the tire remains constant, that the air does not leak out and that the atmospheric pressure remains constant at 14.7 lb/in2 . Answer in units of lb/in2 .
At constant volume,
"\\dfrac{P_1}{T_1}=\\dfrac{P_2}{T_2}"
"P_2=T_2\\times\\dfrac{P_1}{T_2}"
"P_2=(273+7.9)\\times\\dfrac{(24+14.7)}{(26+273)}"
"P_2=36.35\\space lb\/m^2"
Gauge Pressure in the tire, "P_g=36.35-14.7=21.65\\space lb\/m^2"
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