Question #18728

a body of mass 5kg is displaced through a distance of 2m with uniform accleratiom of 3ms-2 calculate work done

Expert's answer

Question#18728

a body of mass 5kg is displaced through a distance of 2m with uniform acceleration of 3ms-2 calculate work done

Solution:

The done work is:

A=FSA = FS , were FF - force due to the body, SS - displacement

According to the Second Newton's Law:

F=ma,F = ma, were mmass,am - mass, a - acceleration


A=maS=532=30JA = m a S = 5 * 3 * 2 = 3 0 J


Answer: 30 J

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