Question

two forces of 10N and 6N act upon a body.the direction of the forces are unknown.the resultant force on the body
1.15N
2.3N
3.17N
4.2N

Answer 1

Two forces of 10N and 6N act upon a body. The direction of the forces are unknown. The resultant force on the body

1.15N

2.3N

3.17N

4.2N

Solution

The resultant force on the body is

$$\bar{F} = \bar{F}_1 + \bar{F}_2 \gg F_{max} = F_1 + F_2$$ $$\bar{F} = \bar{F}_1 + \bar{F}_2 \gg F_{min} = F_1 - F_2$$ $$F_{max} = 10 + 6 = 16N$$

That's why answer 3 is wrong ($F_{max} < 17N$)

$$F_{min} = 10 - 6 = 4N$$

Therefore answers 2 and 4 are wrong ($F_{min} > 3N, F_{-} \min > 2N$).

So right answer is 1 $F_{min} < 15N < F_{max}$

Answer: 1