Question #183556

The pressure or air in a reasonably good vacuum might be 2.0 x 10-5 mmHg. What mass of air exists in a 250mL volume at this pressure and 250C? Take M=28 Kg/kmol for air.


Expert's answer

Let's assume that air in the given conditions can be an ideal gas. Then

pV=mMRT\displaystyle pV = \frac{m}{M} RT

Converting everything to SI units

p=2.01015133.32=266.641015  Pap =2.0 \cdot 10^{-15} \cdot 133.32 = 266.64 \cdot 10^{-15}\; Pa

V=250106  m3V= 250 \cdot 10^{-6} \; m^3

T=25+273=298  KT = 25 + 273 =298\; K

M=28103  kg/molM = 28 \cdot 10^{-3}\; kg/ mol


m=pVMRT=266.641015250106281038.31298=753.71024  kg=7.5371022  kg\displaystyle m = \frac{pVM}{RT} = \frac{266.64 \cdot 10^{-15} \cdot 250 \cdot 10^{-6} \cdot 28 \cdot 10^{-3}}{8.31 \cdot 298} =753.7 \cdot 10^{-24} \; kg = 7. 537 \cdot 10^{-22} \;kg

Answer: 7.5371022  kg7. 537 \cdot 10^{-22} \;kg


LATEST TUTORIALS
APPROVED BY CLIENTS