Question

Moving man starts int he negative direction with a speed of 3m/s but is accelerating in the positive direction with acceleration of 2.75m/s^2. what is his velocity and displacement at the end of 5.00 seconds?

Answer 1

Question

The velocity will be equal $V = V_{0} + a \cdot t = -3 + 2.75 \cdot 5 = -3 + 13.75 = 10.75 \frac{m}{s}$.

The displacement: $d = V_{0} \cdot t + \frac{a \cdot t^{2}}{2} = -3 \cdot 5 + \frac{2.75 \cdot 25}{2} = -15 + 34.375 = 19.375 \, \text{m}$.

Answer: velocity: $10.75 \frac{m}{s}$; displacement: $19.375 \, \text{m}$.