(1-Dimensional Collision) A 100g solid ball approaches a 1kg solid ball which is also approaching the 100g ball. If the initial speeds of both balls are 5m/s, what are the final speeds of the balls?
To be given in question
Motion 1D
M1=100gm =0.1kg
M2=1000gm=1.0kg
u1=u2=5 meter/sec
To be asked in question
v1=?
v2=?
We know that
Momentum conservation law
"m_{1}u_{1}+m_{2}u_{2} =m_{1}v_{1}+m_{2}v_{2} \\rightarrow(1)"
Put value in eqution (1)
"0.1\\times5+1\\times5=0.1\\times v_{1}+1\\times v_{2}"
0.5+5.0="(0.1v_{1}+1v_{2})"
5.5="(0.1v_{1}+1v_{2})\\rightarrow(2)"
We know that
Cofficient of restitution
"e=1"
elastic collision
"v_{1}-v_{2} =u_{2}-u_{1}\\rightarrow(3)"
Put value in eqution (3)
"v_{1}-v_{2}=0"
"v_{1}=v_{2}"
equation (2)put values "v_{1}andv_{2}"
"5.5=1.1v_{1}"
"v_{1}=\\frac{55}{11}"
"v_{1}=5meter \/sec"
Similarly
"v_{1}=v_{2}=5meter\/sec"
Comments
Its very helpful for students.
Leave a comment