Question #18231

The mass and diameter of a planet are twice those of the earth.what will be the period of oscillation of a pendulum on this planet,if it is a second's pendulum on the earth.

Expert's answer

The mass and diameter of a planet are twice those of the earth. what will be the period of oscillation of a pendulum on this planet, if it is a second's pendulum on the earth.

**Answer**

The acceleration due to gravity gg on the surface of a planet of radius RR and mass MM is =GMR2= \frac{GM}{R^2}, where GG is the gravitational constant. Therefore, the value of gg on a planet of mass and radius twice those of the earth would be half its value on the earth surface. Since the time TT of a pendulum varies as 1g\frac{1}{\sqrt{g}}, TT on the planet will be 2\sqrt{2} times its value on the earth surface. Hence the desired period of oscillation is 22s2\sqrt{2}s.

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